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1043번: 거짓말 ↗

Solutions

C++14
2.5 KB | 2526 chars
/*
[1043: 거짓말](https://www.acmicpc.net/problem/1043)

Tier: Gold 4 
Category: data_structures, disjoint_set, graphs, graph_traversal
*/


#include <bits/stdc++.h>

using namespace std;

#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define sortv(vct) sort(vct.begin(), vct.end())
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)

typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;

typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;

typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;

typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;

const double EPS = 1e-8;
const double PI = acos(-1);

template<typename T>
T sq(T x) { return x * x; }

int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }

struct UnionFind {
  int n;
  vector<int> u;

  UnionFind(int n) : n(n) {
    u.resize(n + 1);
    for(int i = 1; i <= n; i++) {
      u[i] = i;
    }
  }

  int find(int k) {
    if(u[u[k]] == u[k]) return u[k];
    else return u[k]=find(u[k]);
  }

  void uni(int a, int b) {
    a = find(a);
    b = find(b);
    if(a < b) u[b] = a;
    else u[a] = b; 
  }
};

ll N, M;
ll tr;
llv1 tr_people;
llv2 party;

void solve() {
  cin >> N >> M;
  cin >> tr;

  UnionFind uf(N + 1);

  tr_people.resize(tr);

  for1(0, tr) {
    cin >> tr_people[i];

    uf.uni(0, tr_people[i]);
  }

  for1(0, M) {
    ll cnt, a;
    llv1 crt;
    cin >> cnt;

    crt.resize(cnt);


    for1(0, cnt){
      cin >> crt[i];
      uf.uni(crt[0], crt[i]);
    }

    party.push_back(crt);
  }

  ll ans = 0;

  for1(0, M) {
    bool flag = true;

    forEachj(party[i]) {
      if(uf.find(j) == 0) flag = false;
    }

    if(flag) ans++;
  }

  cout << ans;
}

int main() {
  ios::sync_with_stdio(0);
  cin.tie(NULL);cout.tie(NULL);
  int tc = 1; // cin >> tc;
  while(tc--) solve();
  
}