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11955번: PROZOR ↗

Solutions

Python 3
1.5 KB | 1570 chars
"""
[11955: PROZOR](https://www.acmicpc.net/problem/11955)

Tier: Silver 3 
Category: implementation, bruteforcing
"""


import sys
from math import sqrt, pi, sin, factorial, ceil, floor
from datetime import datetime, timedelta

SYS_INPUT = True
RECURSION_LIMIT = 10 ** 7
SET_RECURSION = False
BLANK = " "

if SET_RECURSION:
  sys.setrecursionlimit(RECURSION_LIMIT)

inp = lambda : sys.stdin.readline().rstrip() if SYS_INPUT else input()
mii = lambda : [*map(int,inp().split())]
mfi = lambda : [*map(float,inp().split())]
ii = lambda : int(inp())
fi = lambda : float(inp())
isplit = lambda : inp().split()
p = print

def gcd(a, b): return gcd(b, a % b) if b > 0 else a
def lcm(a, b): return a * b // gcd(a, b)


def solve():
  R, S, K = mii()

  l = [list(inp()) for _ in range(R)]

  ans = []
  mx = 0

  for sy in range(R - K + 1):
    for sx in range(S - K + 1):
      cnt = 0
      
      for y in range(sy + 1, sy + K - 1):
        for x in range(sx + 1, sx + K - 1):
          if l[y][x] == '*':
            cnt += 1
      
      if cnt > mx:
        mx = cnt
        ans = [(sy, sx), (sy + K - 1, sx + K - 1)]

  print(mx)
  l[ans[0][0]][ans[0][1]] = '+'
  l[ans[1][0]][ans[1][1]] = '+'
  l[ans[0][0]][ans[1][1]] = '+'
  l[ans[1][0]][ans[0][1]] = '+'

  for i in range(ans[0][0] + 1, ans[1][0]):
    l[i][ans[0][1]] = '|'
    l[i][ans[1][1]] = '|'

  for i in range(ans[0][1] + 1, ans[1][1]):
    l[ans[0][0]][i] = '-'
    l[ans[1][0]][i] = '-'

  for i in l:
    p(''.join(i))

  

if __name__ == "__main__":
  tc = 1
  for t in range(1, tc+1):
    ret = solve()