2.1 KB | 2188 chars
/*
[1374: 강의실](https://www.acmicpc.net/problem/1374)
Tier: Gold 5
Category: data_structures, greedy, sorting, priority_queue
*/
#include <bits/stdc++.h>
using namespace std;
#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define sortv(vct) sort(vct.begin(), vct.end())
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)
typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;
typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;
typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;
const double EPS = 1e-8;
const double PI = acos(-1);
template<typename T>
T sq(T x) { return x * x; }
int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }
ll N, a, b, c;
vector <pll> classes;
void solve() {
cin >> N;
for1(0, N) {
cin >> a >> b >> c;
classes.push_back({b, c}); // {start, end}
}
sort(all(classes));
ll ans = 0;
priority_queue<ll, vector<ll>, greater<ll>> pq; // end_times
for(auto cls : classes) {
if(pq.empty()) {
pq.push(cls.se);
ans = max(ans, 1ll);
continue;
}
ll fastest_end_time = pq.top();
if(fastest_end_time <= cls.fi) {
pq.pop();
pq.push(cls.se);
} else {
pq.push(cls.se);
}
ans = max(ans, (ll) pq.size());
}
cout << ans << "\n";
}
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);cout.tie(NULL);
int tc = 1; // cin >> tc;
while(tc--) solve();
}