2.1 KB | 2095 chars
/*
[14721: 성적표](https://www.acmicpc.net/problem/14721)
Tier: Silver 5
Category: bruteforcing
*/
#include <bits/stdc++.h>
using namespace std;
#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define sortv(vct) sort(vct.begin(), vct.end())
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)
typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;
typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;
typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;
const double EPS = 1e-8;
const double PI = acos(-1);
template<typename T>
T sq(T x) { return x * x; }
int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }
ll n;
pllv1 ar;
ll f(ll x, ll a, ll b) {
return a * x + b;
}
void solve() {
cin >> n;
ar.resize(n);
for1(0, n) cin >> ar[i].first >> ar[i].second;
ll mn = INF;
pll ans;
for(ll a = 1; a <= 100; a++) {
for(ll b = 1; b <= 100; b++) {
ll rss = 0;
for(pll here : ar) {
ll expected = f(here.first, a, b);
ll real = here.second;
rss += sq((real - expected));
}
if(mn > rss) {
mn = rss;
ans = {a, b};
}
}
}
cout << ans.first << " " << ans.second;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);cout.tie(NULL);
int tc = 1; // cin >> tc;
while(tc--) solve();
}