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16317번: Code Cleanups ↗

Solutions

Python 3
960 B | 960 chars
import sys
from math import sqrt, pi, sin, factorial, ceil, floor
from datetime import datetime, timedelta
# sys.setrecursionlimit(10**7)

BLANK = " "

# inp = input
inp = lambda : sys.stdin.readline().rstrip()
mii = lambda x = BLANK : [*map(int,inp().split(x))]
mfi = lambda x = BLANK : [*map(float,inp().split(x))]
ii = lambda : int(inp())
fi = lambda : float(inp())
p = print
def gcd(a, b): return gcd(b, a % b) if b > 0 else a
def lcm(a, b): return a * b // gcd(a, b)


def solve():
	n = ii()
	l = mii()

	last_cleanup = 0
	ans = 0

	for i in range(1, 366):
		dirty_sum = 0

		for dirty in l:
			if dirty <= last_cleanup or i < dirty:
				continue
			
			dirty_sum += i - dirty
		
		if dirty_sum >= 20:
			last_cleanup = i - 1
			ans += 1
	
	dirty_sum = 0
	for dirty in l:
		if dirty <= last_cleanup:
			continue
		
		dirty_sum += 1

	if dirty_sum > 0:
		ans += 1
	p(ans)



if __name__ == "__main__":
  tc = 1

  for t in range(1, tc+1):
    ret = solve()