← Back to List

1647번: 도시 분할 계획 ↗

Solutions

C++14
1.4 KB | 1393 chars
#include <bits/stdc++.h>

#define for1(s,n) for(int i = s; i < n; i++)
#define for1j(s,n) for(int j = s; j < n; j++)
#define foreach(k) for(auto i : k)
#define foreachj(k) for(auto j : k)
#define pb(a) push_back(a)
#define sz(a) a.size()

#define MAX_N 220000
#define MAX_E 1100000

using namespace std;
typedef unsigned long long ull;
typedef long long ll;
typedef vector <int> iv1;
typedef vector <vector<int> > iv2;
typedef vector <ll> llv1;
typedef unsigned int uint;
typedef vector <ull> ullv1;
typedef vector <vector <ull> > ullv2;

int groups[MAX_N];
ll N, M, a, b, c, result, cnt;

struct Edge {
	int here, there;
	ll cost;
	
	Edge(): Edge(0, 0, -1) {}
	Edge(ll h, ll t, ll c): here(h), there(t), cost(c) {}
	
	bool operator <(const Edge& e) const { return cost < e.cost; }
};

int find(int a) {
	if(groups[a] < 0) return a;
	return groups[a] = find(groups[a]);
}

bool merge(int a, int b) {
	a = find(a);
	b = find(b);
	
	if(a == b) return false;
	groups[b] = a;
	
	return true;
}

Edge edges[MAX_E];

int main() {
  ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	
	cin >> N >> M;
	
	for1(0, M) {
		cin >> a >> b >> c;
		
		edges[i] = Edge(a, b, c);
	}
	
	sort(edges, edges+M);
	fill(groups, groups + N, -1);
	
	for(int i = 0; i < M; i++) {
		if(cnt >= N - 2) break;

		if(merge(edges[i].here, edges[i].there)) {
			result += edges[i].cost;
			cnt++;
		}
	}
	
	cout << result;
}