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20232번: Archivist ↗

Solutions

Python 3
217 B | 217 chars
print(['ITMO','SPbSU','SPbSU','ITMO','ITMO','SPbSU','ITMO','ITMO','ITMO','ITMO','ITMO','PetrSU, ITMO','SPbSU','SPbSU','ITMO','ITMO','ITMO','ITMO','SPbSU','ITMO','ITMO','ITMO','ITMO','SPbSU','ITMO'][int(input())-1995])