2.0 KB | 2018 chars
/*
[6198: 옥상 정원 꾸미기](https://www.acmicpc.net/problem/6198)
Tier: Gold 5
Category: data_structures, stack
*/
#include <bits/stdc++.h>
using namespace std;
#define for1(s, e) for(int i = s; i < e; i++)
#define for1j(s, e) for(int j = s; j < e; j++)
#define forEach(k) for(auto i : k)
#define forEachj(k) for(auto j : k)
#define sz(vct) vct.size()
#define all(vct) vct.begin(), vct.end()
#define uniq(vct) sort(all(vct));vct.erase(unique(all(vct)), vct.end())
#define fi first
#define se second
#define INF (1ll << 60ll)
typedef unsigned long long ull;
typedef long long ll;
typedef ll llint;
typedef unsigned int uint;
typedef unsigned long long int ull;
typedef ull ullint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef pair<double, int> pdi;
typedef pair<string, string> pss;
typedef vector<int> iv1;
typedef vector<iv1> iv2;
typedef vector<ll> llv1;
typedef vector<llv1> llv2;
typedef vector<pii> piiv1;
typedef vector<piiv1> piiv2;
typedef vector<pll> pllv1;
typedef vector<pllv1> pllv2;
typedef vector<pdd> pddv1;
typedef vector<pddv1> pddv2;
const double EPS = 1e-8;
const double PI = acos(-1);
template<typename T>
T sq(T x) { return x * x; }
int sign(ll x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(int x) { return x < 0 ? -1 : x > 0 ? 1 : 0; }
int sign(double x) { return abs(x) < EPS ? 0 : x < 0 ? -1 : 1; }
ll N;
llv1 ar;
llv1 ans;
stack <ll> stk;
void solve() {
cin >> N;
ar.resize(N);
ans.resize(N);
for1(0, N) cin >> ar[i];
// 스택에 인덱스를 넣는다.
for1(0, N) {
while(!stk.empty() && ar[stk.top()] <= ar[i]) {
ll prev = stk.top(); stk.pop();
ll here = i;
ans[prev] = here - prev - 1;
}
stk.push(i);
}
while(!stk.empty()) {
ll here = stk.top(); stk.pop();
ans[here] = N - here - 1;
}
ll sm = 0;
for1(0, N) {
sm += ans[i];
}
cout << sm;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);cout.tie(NULL);
int tc = 1; // cin >> tc;
while(tc--) solve();
}